(x)=x^2+10x-200

Solution for (x)=x^2+10x-200 equation:

(x)=x^2+10x-200

We move all terms to the left:

(x)-(x^2+10x-200)=0

We get rid of parentheses

-x^2+x-10x+200=0

We add all the numbers together, and all the variables

-1x^2-9x+200=0

a = -1; b = -9; c = +200;
Δ = b2-4ac
Δ = -92-4·(-1)·200
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{881}}{2*-1}=\frac{9-\sqrt{881}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{881}}{2*-1}=\frac{9+\sqrt{881}}{-2}
$